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Simplifying 3 + -16x + -8x2 = 0 Solving 3 + -16x + -8x2 = 0 Solving for variable 'x'. Begin completing the square. Divide all terms by -8 the coefficient of the squared term: Divide each side by '-8'. -0.375 + 2x + x2 = 0 Move the constant term to the right: Add '0.375' to each side of the equation. -0.375 + 2x + 0.375 + x2 = 0 + 0.375 Reorder the terms: -0.375 + 0.375 + 2x + x2 = 0 + 0.375 Combine like terms: -0.375 + 0.375 = 0.000 0.000 + 2x + x2 = 0 + 0.375 2x + x2 = 0 + 0.375 Combine like terms: 0 + 0.375 = 0.375 2x + x2 = 0.375 The x term is 2x. Take half its coefficient (1). Square it (1) and add it to both sides. Add '1' to each side of the equation. 2x + 1 + x2 = 0.375 + 1 Reorder the terms: 1 + 2x + x2 = 0.375 + 1 Combine like terms: 0.375 + 1 = 1.375 1 + 2x + x2 = 1.375 Factor a perfect square on the left side: (x + 1)(x + 1) = 1.375 Calculate the square root of the right side: 1.17260394 Break this problem into two subproblems by setting (x + 1) equal to 1.17260394 and -1.17260394.Subproblem 1
x + 1 = 1.17260394 Simplifying x + 1 = 1.17260394 Reorder the terms: 1 + x = 1.17260394 Solving 1 + x = 1.17260394 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 1.17260394 + -1 Combine like terms: 1 + -1 = 0 0 + x = 1.17260394 + -1 x = 1.17260394 + -1 Combine like terms: 1.17260394 + -1 = 0.17260394 x = 0.17260394 Simplifying x = 0.17260394Subproblem 2
x + 1 = -1.17260394 Simplifying x + 1 = -1.17260394 Reorder the terms: 1 + x = -1.17260394 Solving 1 + x = -1.17260394 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = -1.17260394 + -1 Combine like terms: 1 + -1 = 0 0 + x = -1.17260394 + -1 x = -1.17260394 + -1 Combine like terms: -1.17260394 + -1 = -2.17260394 x = -2.17260394 Simplifying x = -2.17260394Solution
The solution to the problem is based on the solutions from the subproblems. x = {0.17260394, -2.17260394}
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